IPL: Mumbai-Hyderabad match today, not easy path for SRH
Sunrisers Hyderabad have lost their first two matches this season
After losing their first two matches in this season of the IPL, the Sunrisers Hyderabad team would like to return from the match against Mumbai Indians on Saturday. Mumbai’s team has won one of its two matches this season.
It will be interesting to see whether the Hyderabad team takes on New Zealand batsman Kane Williamson in this match or not, who did not get a place in the playing eleven in the first two matches.
In the last match against Royal Challengers Bangalore, the Hyderabad batsmen stumbled after a good start due to which they had to face defeat in the match.
There has been a demand to give Williamson a place in the team and former Indian cricketers Virender Sehwag and Sanjay Manjrekar have said that Williamson’s inclusion in the playing eleven is necessary for the Hyderabad batting lineup.
Mumbai has bowlers like Trent Boult and Jaspreet Bumrah. In such a situation, Hyderabad needs some batsmen who can play long innings. In this match, the battle between Bolt and Hyderabad captain David Warner can be seen.
Apart from this, it will be a challenge for the middle and lower order batsmen of Mumbai to face spinner Rashid Khan.
Mumbai’s batting was nothing special in the last match. However, he has batsmen in the middle and lower order who have the ability to play big shots.
Mumbai had to face defeat against Bangalore while they won in a close match against Kolkata Knight Riders.
It will also be interesting to see if the Hyderabad team will give an opportunity to fast bowler Sandeep Sharma, who swings the ball. Bhuvneshwar Kumar and Jason Holder bowled well against the new ball against Bangalore.
Chennai pitch is helpful for spinners and the game starts slowing down. In such a situation, the team batting first will get an advantage compared to the opposing team.
Hyderabad had to face defeat in both the matches while chasing the target while Mumbai’s team won the last match defending the score.